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System Name | "Nave Espacial" |
---|---|
Processor | AMD Ryzen 7 7800X3D |
Motherboard | MSI B650M Project Zero |
Cooling | Corsair H150i Elite LCD XT |
Memory | Corsair Vengeance RGB 64GB (2x32GB) DDR5 6000MT/s CL30 |
Video Card(s) | MSI GeForce RTX 4090 GAMING X SLIM |
Storage | Samsung 990 PRO 4TB + Acer Predator GM7 4TB |
Display(s) | Corsair Xeneon 27QHD240 |
Case | Corsair 2500X (black) |
Audio Device(s) | Corsair HS80 Wireless Headset |
Power Supply | Corsair RM1200x Shift |
Mouse | Corsair Darkstar Wireless |
Keyboard | Corsair K65 Pro Mini 65% |
Software | Windows 11, iCUE |
I was trying to figure this out on my own, but I thought I might as well discuss it publicly here.
I own a 4090 and I'm (once again) anxiously concerned about a potential melting connector. My case is small, and the AIO tubes rest directly on top of the connector area, so worst case scenario I'd be facing having to replace the GPU, PSU and AIO. Really fun stuff.
I have come to consider undervolting the thing vs. power limiting it to 4080 territory to prevent heat build-up at the connector... but then I remembered the IT lessons in high school, and how Joule heating factors in only current (amps), not really watts (amps by volts) as a whole. The formula is
That being said, I'm not quite confident in my conclusions. Any mind brither than mine that might chime in? Any electrical engineers in the room? Thanks in advance.
I own a 4090 and I'm (once again) anxiously concerned about a potential melting connector. My case is small, and the AIO tubes rest directly on top of the connector area, so worst case scenario I'd be facing having to replace the GPU, PSU and AIO. Really fun stuff.
I have come to consider undervolting the thing vs. power limiting it to 4080 territory to prevent heat build-up at the connector... but then I remembered the IT lessons in high school, and how Joule heating factors in only current (amps), not really watts (amps by volts) as a whole. The formula is
...meaning that the real culprits for the heating up would be amps flowing through the cable multiplied by the resistance of the mating point and the time under load. All this tells me that voltage is completely irrelevant, thus making undervolting not helpful to prevent this at all.Heat = I² · R · t
That being said, I'm not quite confident in my conclusions. Any mind brither than mine that might chime in? Any electrical engineers in the room? Thanks in advance.
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