It may be able to boost higher due to the lower power usage and heat-load. That tends to hold back the mobile 13th/14th Gen cpus a lot.

they should throw 128 old atom cores int here, to really take the MT crown.

12% is not exactly "crushing" lets be real here.

More treading of water.

Regarding the removal of HT, is Intel using the "rentable units' tech with these ?

BobaganooshIt may be able to boost higher due to the lower power usage and heat-load. That tends to hold back the mobile 13th/14th Gen cpus a lot.

Yeah, I suspect ARL is able to maintain higher clocks for the duration. The E-cores are already clocked higher in ARL, so that might be entirely responsible for the performance gain. Cinebench is a fun number and all, but a program designed to max out all the cores is not all that representative of daily usage. Where I see P+E struggle is on mixed use, where a program only occasionally needs as much multithreaded power as it can get, and that’s usually when P+E falls on its face.

Vya Domus12% is not exactly "crushing" lets be real here.

I've calculated the difference of the multi-threaded performance as follows: ( 31,854 * 100.0 / 35,481 ) - 100.0 = ~10.22%.

Note: In HPC world a difference greater than 5% is considered as a good improvement. On a Big Data set it will reduce processing time.

I like how there is different math from different people. From the same data set:

GGforever says 18%
Vya Domus says 12%
ScaLibBDP says 10%

Does anyone want to show math for 5%? 25%?

DavenI like how there is different math from different people. From the same data set:

GGforever says 18%
Vya Domus says 12%
ScaLibBDP says 10%

Does anyone want to show math for 5%? 25%?

I've described how I've calculated the difference. Next, I've just used the Microsoft Copilot to verify if my way is wrong. Here is a log of my "conversation" with Microsoft Copilot.

The result depends on what number is used as a base to compare with another number. So two possible cases:

...31,854 is lower than 35,481...
or
...35,481 is greater than 31,854...

Both results are Valid!

...
[ ScaLibBDP ] Calculate for how many percent 31,854 is lower than 35,481

[ Copilot ]
To find how much percent 31,854 is lower than 35,481, you can use the following formula:
Percent Lower=DifferenceOriginal Number×100\text{Percent Lower} = \frac{ \text{Difference} }{ \text{Original Number} } \times 100
Let's plug in the values:
\text{Difference} = 35,481 - 31,854 = 3,627 $$ $$ \text{Original Number} = 35,481
Now, use the formula to calculate the percent lower:
Percent Lower=3,62735,481×100≈10.22%\text{Percent Lower} = \frac{3,627}{35,481} \times 100 \approx 10.22\%
So, 31,854 is approximately 10.22% lower than 35,481



...
[ ScaLibBDP ] Calculate for how many percent 35,481 is greater than 31,854

[ Copilot ]
To find how much percent 35,481 is greater than 31,854, you can use the following formula:
Percent Greater=DifferenceOriginal Number×100\text{Percent Greater} = \frac{ \text{Difference} }{ \text{Original Number} } \times 100
Let's plug in the values:
\text{Difference} = 35,481 - 31,854 = 3,627 $$ $$ \text{Original Number} = 31,854
Now, use the formula to calculate the percent greater:
Percent Greater=3,62731,854×100≈11.39%\text{Percent Greater} = \frac{3,627}{31,854} \times 100 \approx 11.39\%
So, 35,481 is approximately 11.39% greater than 31,854

ScaLibBDPI've calculated the difference of the multi-threaded performance as follows: ( 31,854 * 100.0 / 35,481 ) - 100.0 = ~10.22%.

Note: In HPC world a difference greater than 5% is considered as a good improvement. On a Big Data set it will reduce processing time.

Good improvement is Zen 4 to Zen 5, for example 9800X3D vs. 7800X3D under Linux where the improvement is ~25% using your formula.
Those 10% we're not even sure of because both Intel CPUs can scale from 45W to 160W, so unless both CPUs run at the same power limits with similar cooling it's not a useful comparison for laptop chips.

DavenI like how there is different math from different people. From the same data set:

GGforever says 18%
Vya Domus says 12%
ScaLibBDP says 10%

Does anyone want to show math for 5%? 25%?

The median for the 14900HX is ~30k, thats what I used....

ok but does anyone care?

ZoneDymook but does anyone care?

If you need a new windows laptop to do some rendering on and can’t find a zen5 laptop?

Didn’t Intel update the E-core u-arch? Isn’t it supposed to be significantly faster now?

A 14900HX can reach 35,000 points in R23. There is lots of room to go beyond that if you use ThrottleStop to do some undervolting.

unclewebbA 14900HX can reach 35,000 points in R23. There is lots of room to go beyond that if you use ThrottleStop to do some undervolting.

Sure, but better to stick with the median value when the tested config details are under wraps.
ThrottleStop is great btw, I use it to disable bd_prochot on my MBP (dead battery, lol).. can't help the igpu though...

ScaLibBDPNote: In HPC world a difference greater than 5% is considered as a good improvement. On a Big Data set it will reduce processing time.

Okay, but this is just a consumer processor. Yes, it's not from the Ultra low power consumption series. And yes, I know that workstations are also assembled with consumer processors. But still, when you say HPC, I somehow understand it as supercomputers with many orders of magnitude more productive than a laptop.